化简x-2分之2x-6除以(x-2分之5-x-2)
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楼上的好像算错了。
应为:原式=[2(x-3)/(x-2)]÷[5/(x-2)-(x+2)]
=[2(x-3)/(x-2)]÷{[5-(x+2)(x-2)]/(x-2)}
=[2(x-3)/(x-2)]÷[(5-x²+4)/(x-2)]
=[2(x-3)/(x-2)]÷[-(x+3)(x-3)/(x-2)]
=-2(x-3)(x-2)/[(x-2)(x+3)(x-3)]
=-2/(x+3)
应为:原式=[2(x-3)/(x-2)]÷[5/(x-2)-(x+2)]
=[2(x-3)/(x-2)]÷{[5-(x+2)(x-2)]/(x-2)}
=[2(x-3)/(x-2)]÷[(5-x²+4)/(x-2)]
=[2(x-3)/(x-2)]÷[-(x+3)(x-3)/(x-2)]
=-2(x-3)(x-2)/[(x-2)(x+3)(x-3)]
=-2/(x+3)
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(2x-6)/(x-2)÷ [(5-x)/(x-2) -2]
=(2x-6)/(x-2)÷ [(5-x)/(x-2) -2(x-2)/(x-2)]
=(2x-6)/(x-2)÷ (5-x-2x+4)/(x-2)
=(2x-6)/(x-2)* (x-2)/ (9-3x)
=2(x-3)/3(3-x)
=-2/3
=(2x-6)/(x-2)÷ [(5-x)/(x-2) -2(x-2)/(x-2)]
=(2x-6)/(x-2)÷ (5-x-2x+4)/(x-2)
=(2x-6)/(x-2)* (x-2)/ (9-3x)
=2(x-3)/3(3-x)
=-2/3
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