Question

编写利用结构体实现复数的加、减、乘、除=运算的C语言程序

期末课程设计题目 ： 题 目 结构 表示 回传方式 操作 实数对 (实部,虚部) 实数对结构体指针 当前对象 基本操作恩 大概要求就是这样…… 高手帮忙 整一哈~！

Answer 1

C＋＋可以用类，然后重载运算符
C可以用struct来代替类，然后写相应函数来就行了，一回事
下面是随手写的，大概就这样子吧
struct complex{
int real;
int imag;
}a,b;

complex Plus(complex a,complex b)
{
complex result;
result->real = a->real + b->real;
result->imag = a->imag + b->imag;
return result;
}

Answer 2

#include <stdio.h>

typedef struct Complex
{
double real;
double imag;
}Complex;

Complex add(Complex c1, Complex c2)
{
Complex c3;
c3.real = c1.real + c2.real;
c3.imag = c1.imag + c2.imag;
return c3;
}

Complex sub(Complex c1, Complex c2)
{
Complex c3;
c3.real = c1.real - c2.real;
c3.imag = c1.imag - c2.imag;
return c3;
}

Complex mul(Complex c1, Complex c2)
{
Complex c3;
c3.real = c1.real * c2.real - c1.imag * c2.imag;
c3.imag = c1.imag * c2.real + c1.real * c2.imag;
return c3;
}

Complex div(Complex c1, Complex c2)
{
Complex c3;
double u = c2.real * c2.real + c2.imag * c2.imag;
c3.real = (c1.real * c2.real + c1.imag * c2.imag) / u;
c3.imag = (c1.imag * c2.real - c1.real * c2.imag) / u;
return c3;
}

void print(Complex c)
{
printf("%lf+%lfi", c.real, c.imag);
}

int main()
{
Complex c1 = {5, 6};
Complex c2 = {3, 4};
print(add(c1, c2));
printf("\n");
print(sub(c1, c2));
printf("\n");
print(mul(c1, c2));
printf("\n");
print(div(c1, c2));
printf("\n");
return 0;
}