Question

设S=(x-1)四次方+4(x-1)三次方+6(x-1)平方+4x-3,则S等于

选择题 A .X四次方 BX四次方 +1 C(X-2)四次方 DX四次方+4

Answer 1

S=(x-1)⁴+4(x-1)³ +6(x-1)²+4x-3
=(x-1)⁴+4(x-1)³ +6(x-1)²+4(x-1)+1
=[(x-1)+1]⁴
=x⁴
选A。

Answer 2

S=(x-1)四次方+4(x-1)三次方+6(x-1)平方+4x-3
=(x-1)四次方+4(x-1)三次方+4(x-1)平方+2(x-1)平方+4x-3
=(x-1)²[(x-1)²+4(x-1)+4]+2(x-1)平方+4x-3
=(x-1)²(x-1+2)²+2(x-1)平方+4x-3
=[(x-1)(x+1)]²+2(x-1)平方+4x-3
=x^4-2x²+1+2x²-4x+2+4x-3
=x^4

选择 A

Answer 3

S=(x-1)四次方+4(x-1)三次方+6(x-1)平方+4(x-1) +1
=(x-1+1)^4=x^4
选A

Answer 4

a~我确定哦~

Answer 5

A