急求答案!! 求:
lim(cos(x/2)cos(x/4)···cos(x/2^n))速度啊!在线等!n是变量的情况下···忘记加了...
lim(cos(x/2)cos(x/4)···cos(x/2^n))
速度啊! 在线等!
n是变量的情况下···忘记加了 展开
速度啊! 在线等!
n是变量的情况下···忘记加了 展开
展开全部
这里需要做个小小的变换:
sinx=2cos(x/2)sin(x/2)
=2^2cos(x/2)cos(x/4)sin(x/4)
=···
=2^ncos(x/2)cos(x/4)cos(x/8)···(x/2^n)sin(x/2^n)
所以lim(cos(x/2)cos(x/4)···cos(x/2^n))=lim(sinx/2^n * 1/sin(x/2^n))
=lim(x/2^n/sin(x/2^n) * sinx/x)
=sinx/x
(变量时n吧?)
sinx=2cos(x/2)sin(x/2)
=2^2cos(x/2)cos(x/4)sin(x/4)
=···
=2^ncos(x/2)cos(x/4)cos(x/8)···(x/2^n)sin(x/2^n)
所以lim(cos(x/2)cos(x/4)···cos(x/2^n))=lim(sinx/2^n * 1/sin(x/2^n))
=lim(x/2^n/sin(x/2^n) * sinx/x)
=sinx/x
(变量时n吧?)
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