Question

C语言作业求助

若a=3,b=4,c=5,x=1.2,y=2.4,z=-3.6,u=51274,n=128765,c1=‘a‘,c2=‘b‘。写出程序，使之输出下面的结果
a=3 b=4 c=5
x=1.200000,y=2.400000,z=-3.600000
x+y=3.60 y+z=-1.20 z+x=-2.40
u=51274 n=127865
c1=‘a‘ or c1=97
c2=‘b‘or c2=98
发到邮箱 yqpdcl@126.com 谢谢了

Answer 1

#include <stdio.h>
#include <stdlib.h>
main()
{
int a=3,b=4,c=5;
float x=1.2,y=2.4,z=-3.6;
long u=51274,n=128765;
char c1='a',c2='b';
printf("a=%d b=%d c=%d\n",a,b,c);
printf("x=%.6f,y=%.6f,z=%.6f\n",x,y,z);
printf("x+y=%.2f y+z=%.2f z+x=%.2f\n",x+y,y+z,z+x);
printf("u=%ld n=%ld\n",u,n);
printf("c1='%c'orc1=%d\n",c1,c1);
printf("c2='%c'orc2=%d\n",c2,c2);
system("pause");
}

Answer 2

#include <stdio.h>

int main(void)
{
int a=3,b=4,c=5;
float x=1.2,y=2.4,z=-3.6;
unsigned int u=51274,n=128765 ;
char c1='a',c2='b';

printf("a=%d b=%d c=%d\nx=%f,y=%f,z=%f\n"
"x+y=%.2f y+z=%.2f z+x=%.2f\n"
"u=%u n=%u\n"
"c1='%c' or c1=%d\n"
"c2='%c' or c2=%d\n" ,
a ,b,c ,x,y,z,x+y,y+z,z+x,
u,n,c1,c1,c2,c2) ;

return 0 ;
}

Answer 3

int a=3,b=4,c=5;
float x=1.2,y=2.4,z=-3.6;
long u=51274,n=128765;
char c1='a',c2='b';
printf("a=%d b=%d c=%d\n",a,b,c);
printf("x=%.6f,y=%.6f,z=%.6f\n",x,y,z);
printf("x+y=%.2f y+z=%.2f z+x=%.2f\n",x+y,y+z,z+x);
printf("u=%ld n=%ld\n",u,n);
printf("c1='%c'orc1=%d\n",c1,c1);
printf("c2='%c'orc2=%d\n",c2,c2);
system("pause");

Answer 4

自己写吧