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解：原式=[(2y-6)/(y²-4y+4)]×[(y+3)/1]÷[(9-y²)/(12-6y)]
=[2(y-3)/(y-2)²]×[(y+3)/1]÷{-(y²-9)/[-(6y-12)]}
=[2(y-3)/(y-2)²]×[(y+3)/1]÷{(y²-9)/[6(y-2)]}
=[2(y-3)/(y-2)²]×[(y+3)/1]×[6(y-2)/(y+3)(y-3)]
=6/(y-2)
=[2(y-3)/(y-2)²]×[(y+3)/1]÷{-(y²-9)/[-(6y-12)]}
=[2(y-3)/(y-2)²]×[(y+3)/1]÷{(y²-9)/[6(y-2)]}
=[2(y-3)/(y-2)²]×[(y+3)/1]×[6(y-2)/(y+3)(y-3)]
=6/(y-2)
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