Question

如何使UIWebView响应Touch事件

Answer 1

UIWebView响应不了Touch事件，很久以前就很难解决。最后有一个叫做UICWebView的东西，虽然用了private api，但是可以用。不过－－－－UICWebView或者任何用UIWebDocumentView获得事件的方法在iOS4 100%会出错（因为UIWebDocumentView这个东西没了）。用下面的方法可以让UIWebView响应Touch事件，而且不会影响滚动拖拽的bouncing。

如果需要touch的个数或者坐标，也很简 单，不过需要自己修改代码里的JavaScript。

- (void)viewDidLoad {
[super viewDidLoad];
self.webView.delegate=self;
NSString *resourcePath = [ [NSBundle mainBundle] resourcePath];
NSString *filePath = [resourcePath stringByAppendingPathComponent:@"test.html"];
NSString *htmlstring=[[NSString alloc] initWithContentsOfFile:filePath encoding:NSUTF8StringEncoding error:nil];
NSString *newHTMLString=[htmlstring stringByAppendingString:@"<script language="javascript">document.ontouchstart=function(){ document.location="myweb:touch:start"; }; document.ontouchend=function(){ document.location="myweb:touch:end"; }; document.ontouchmove=function(){ document.location="myweb:touch:move"; } </script>"];
[self.webView loadHTMLString:newHTMLString baseURL:[NSURL fileURLWithPath:[[NSBundle mainBundle] bundlePath]]];
[htmlstring release];
}
- (BOOL)webView:(UIWebView*)webView shouldStartLoadWithRequest:(NSURLRequest*)request navigationType:(UIWebViewNavigationType)navigationType {
NSString *requestString = [[request URL] absoluteString];
NSArray *components = [requestString componentsSeparatedByString:@":"];
if ([components count] > 1 && [(NSString *)[components objectAtIndex:0] isEqualToString:@"myweb"]) {
if([(NSString *)[components objectAtIndex:1] isEqualToString:@"touch"])
{
NSLog(@"%@",[components objectAtIndex:2]);
}
return NO;
}
return YES;
}