求解高数全微分!!过程!!!
2016-06-27
展开全部
Zx=[(x-y)-(x+y)]/(x+y)²=-2y/(x+y)²
Zy=[(x-y)-(x+y)(-1)]/(x+y)²=2x/(x+y)²
dz=Zxdx+Zydy=-2y/(x+y)² dx+2x/(x+y)² dy
Zy=[(x-y)-(x+y)(-1)]/(x+y)²=2x/(x+y)²
dz=Zxdx+Zydy=-2y/(x+y)² dx+2x/(x+y)² dy
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