Question

怎么写一个c++程序，要求用递归函数将十进制数转化成十六进制数？

Answer 1

#include<stdio.h>
Transcoding10_16(int i)
{
int m;
char n;
if(i>15)
{
Transcoding10_16(i/16);
m=i%16;
if(m>0&&m<10)print("%d",m);
else {n='A'+(char)(m-10);print("%lf",n);}
}
else return i;
}
main()
{
int m;
m=123;//提供你修改的转换数据。也可以scanf录入；
Transcoding10_2(m);
}

Answer 2

供参考……
#include "stdafx.h"
#include "iomanip.h"

void Recursion10to16(int i){
char m;
if(i>15) Recursion10to16(i/16);
if((m=i%16+'0')>0x39) m+=7;
cout << m;
}

void main(void){
int nDec;
cout << "请输入一个十进制整数...\n" << "nDec=";
cin >> nDec;
cout << "nHex=0x";
Recursion10to16(nDec);
cout << endl;
}