因式分解:xy-x²y²-x³y³
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解:
xy-x²y²-x³y³
=-xy(x²y²+xy-1)
=-xy(x²y²+xy+¼ -5/4)
=-xy[(xy+½)² -5/4]
=-xy[xy+ (1+√5)/2][xy+ (1-√5)/2]
xy-x²y²-x³y³
=-xy(x²y²+xy-1)
=-xy(x²y²+xy+¼ -5/4)
=-xy[(xy+½)² -5/4]
=-xy[xy+ (1+√5)/2][xy+ (1-√5)/2]
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2016-09-27
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xy-x²y²-x³y³
= xy(1-xy-x²y²)
= xy(5/4-1/4-xy-x²y²)
= xy{5/4-(1/2-xy)²}
= xy(√5/2+1/2-xy)(√5/2-1/2+xy)
= xy(1-xy-x²y²)
= xy(5/4-1/4-xy-x²y²)
= xy{5/4-(1/2-xy)²}
= xy(√5/2+1/2-xy)(√5/2-1/2+xy)
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2016-09-27
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=xy(1-xy-x^2y^2)
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xy-x²y²-x³y³
=xy(1-xy-x²y²)
=xy(1-xy-x²y²)
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