Question

从键盘上输入10个整数，并求出这10个数中所有奇数的和与所有偶数之和要求：分别用while,do ...while

for三种循环结构实现，要C++

Answer 1

#include <stdio.h>

long main(void)
{
long a[10] = {0};
long i, sum1, sum2;

printf("输入10个数以空格分隔:\n");
for (i=0,sum1=0,sum2=0; i<10; ++i)
{
scanf("%d", &a[i]);
if (a[i]%2 == 0)
sum1 += a[i];
else
sum2 += a[i];
}

printf("偶数和为: %d\n", sum1);
printf("奇数和为: %d\n", sum2);

return 0;
}