函数问题，求解答步骤
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f(x)= (1/4)^x -(1/2)^x +1
=(1/2)^(2x) - (1/2)^x +1
= [(1/2)^x - 1/2]^2 + 3/4
x∈[ -3, 2]
min f(x) = f(1) = 3/4
f(-3) =[(1/2)^(-3) - 1/2]^2 + 3/4
= 225/4 +3/4
= 57
f(2) = [(1/2)^(2) - 1/2]^2 + 3/4
= 1/16 +3/4
=7/16
值域=[3/4, 57]
=(1/2)^(2x) - (1/2)^x +1
= [(1/2)^x - 1/2]^2 + 3/4
x∈[ -3, 2]
min f(x) = f(1) = 3/4
f(-3) =[(1/2)^(-3) - 1/2]^2 + 3/4
= 225/4 +3/4
= 57
f(2) = [(1/2)^(2) - 1/2]^2 + 3/4
= 1/16 +3/4
=7/16
值域=[3/4, 57]
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