Question

c语言一元二次方程ax2+bx+c=0的实根,然后输出

#include <stdio.h>
#include <math.h>
main()
{
double a,b,c,p,d,x1,x2;
scanf("%f%f%f",&a,&b,&c);
p=sqrt(b*b-4*a*c);
d=2*a;
x1=(-b+p)/d;
x2=(-b-p)/d;
if(p>0)
printf("x1=%0.2f\n,x2=%0.2f\n",x1,x2);
else if(p==0)
{
x1=x2=(-b)/d;
printf("x1=x2=%0.2f\n",x1);
}
else printf("无实根");
return 0;
}
求纠错

Answer 1

scanf("%f%f%f",&a,&b,&c);改为：scanf("%lf%lf%lf",&a,&b,&c);