Question

求解一道二元一次方程，需要过程

求解一道二元一次方程，需要过程2000+5000+500X=725Y
4000+3000+100Y=16000X

Answer 1

如图

Answer 2

2000+5000+500x=725y
-500x+725y = 7000
-20x+29y = 280 (1)

4000+3000+100y=16000x
16000x-100y =7000
160x-y =70 (2)
(1) +29(2)
4620x =2310
x= 1/2
from (2)
160x-y =70
80-y=170
y=-90
(x,y) = ( 1/2, -90)