Question

这道三角函数题怎么做

这道三角函数题怎么做具体步骤有吗

Answer 1

请采纳

Answer 2

sinα= 3/5 , tan(α+β)=2
solution:
sinα=3/5
=>tanα=-3/4
tan(α+β)=2
(tanα+tanβ)/(1-tanα.tanβ)=2
2(tanα+tanβ)=1-tanα.tanβ
2(-3/4+tanβ)=1+(3/4)tanβ
2(-3+4tanβ)=4+3tanβ
5tanβ =10
tanβ =2