Question

Java计算并输出1-1/3+1/5-1/7+……,直到最后一项的绝对值小于eps为止

Answer 1

你好！eps具体是多少，你可以改代码中变量值
public static void main(String[] args) {

double eps = 0.001;
double item = 1.0, sum = 0.0;
int i = 1;
while (Math.abs(item) >= eps) {
sum += item;
if (i % 2 == 0)
item = 1.0 / (2 * i + 1);
else
item = -1.0 / (2 * i + 1);
i++;
}
System.out.println("sum = "+sum);
}