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高等数学曲线积分,求
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原式=∫(0,π/2) costsint*√(sin^2t+cos^2t)dt
=(1/2)*∫(0,π/2) sin(2t)dt
=-(1/4)*cos(2t)|(0,π/2)
=-(1/4)*(-1-1)
=1/2
=(1/2)*∫(0,π/2) sin(2t)dt
=-(1/4)*cos(2t)|(0,π/2)
=-(1/4)*(-1-1)
=1/2
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