分解因式(2+1)(2^2+1)(2^4+1)(2^8+1)…(2^64+1)+1
3个回答
展开全部
(2+1)(2^2+1)(2^4+1)(2^8+1)…(2^64+1)+1
=3(2^2+1)(2^4+1)(2^8+1)…(2^64+1)+1
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)…(2^64+1)+1
=(2^4-1)(2^4+1)(2^8+1)…(2^64+1)+1
=2^128-1+1
=2^128
=3(2^2+1)(2^4+1)(2^8+1)…(2^64+1)+1
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)…(2^64+1)+1
=(2^4-1)(2^4+1)(2^8+1)…(2^64+1)+1
=2^128-1+1
=2^128
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
展开全部
(2+1)(2^2+1)(2^4+1)(2^8+1)…(2^64+1)+1
=(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)…(2^64+1)+1
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)…(2^64+1)+1
=2^128-1+1
=2^128
=(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)…(2^64+1)+1
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)…(2^64+1)+1
=2^128-1+1
=2^128
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询