
(x-2y)^2+(x-y)(x-2y)-2(x-3y)(x-y),其中x=-4,y=5/2
3个回答
展开全部
解:(x-2y)²+(x-y)(x-2y)-2(x-3y)(x-y)
=(x-2y)[(x-2y)+(x-y)]-2(x-3y)(x-y)
=(x-2y)(2x-3y)-2(x-3y)(x-y)
=2x²-3xy-4xy+6y²-2(x²-xy-3xy+3y²)
=2x²-7xy+6y²-2x²+8xy-6y²
=xy
x=-4,y=5/2
则原式=xy
=-4×5/2
=-10
祝你开心
=(x-2y)[(x-2y)+(x-y)]-2(x-3y)(x-y)
=(x-2y)(2x-3y)-2(x-3y)(x-y)
=2x²-3xy-4xy+6y²-2(x²-xy-3xy+3y²)
=2x²-7xy+6y²-2x²+8xy-6y²
=xy
x=-4,y=5/2
则原式=xy
=-4×5/2
=-10
祝你开心
展开全部
(x-2y)^2+(x-y)(x-2y)-2(x-3y)(x-y)
=x^2-4xy+4y^2+x^2-xy-2xy+2y^2-2x^2+6xy+2xy-6y^2
=xy
当x=-4,y=5/2时
原式=-10
=x^2-4xy+4y^2+x^2-xy-2xy+2y^2-2x^2+6xy+2xy-6y^2
=xy
当x=-4,y=5/2时
原式=-10
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