Question

（1）（x-2分之3x-x+2分之x)除以x^2-4分之x (2)2x-4分之x-3除以（x-2分之5-x-2)

Answer 1

（1）（x-2分之3x-x+2分之x)除以x^2-4分之x
={[3x(x+2)-x(x-2)]/(x+2)(x-2)}÷[x/(x+2)(x-2)]
=[3x(x+2)-x(x-2)]/x
=3(x+2)-(x-2)
=3x+6-x+2
=2x+8
(2)2x-4分之x-3除以（x-2分之5-x-2)
=[(x-3)/2(x-2)]÷{[5-(x-2)(x+2)]/(x-2)]
=[(x-3)/2]÷[5-(x-2)(x+2)]
=[(x-3)/2]÷(9-x^2)
=-(x-3)/[2(x+3)(x-3)]
=-1/(2x+6)