计算: (1-1-X分之1)(X的平方分之1-1)÷( - X分之X+1)
先化简,再求值:2m-4分之3-m÷(m+2-m-2分之5),其中m=2分之1共有两题,帮帮小弟一忙。。...
先化简,再求值:2m-4分之3-m ÷(m+2 - m-2分之5),其中m=2分之1 共有两题,帮帮小弟一忙。。
展开
展开全部
解1题
原式=[1-1/(1-x)]×[(1/x²)-1]÷[-(x+1)/x]
=[1+1/(x-1)]×[(1/x²)-(x²/x²)]×[-x/(x+1)]
=[(x-1+1)/(x-1)]×[(1-x²)/x²]×[-x/(x+1)]
=[x/(x-1)]×[-(x+1)(x-1)/x²]×[-x/(x+1)]
=1
解2题
原式=[(3-m)/(2m-4)]÷[(m+2)-5/(m-2)]
={(3-m)/[2(m-2)]}÷[(m+2)(m-2)/(m-2)-5/(m-2)]
={-(m-3)/[2(m-2)]}÷[(m²-4-5)/(m-2)]
={-(m-3)/[2(m-2)]}×{(m-2)/[(m+3)(m-3)]}
=-1/[2(m+3)]
=-1/[2×(1/2+3)]
=-1/(1+6)
=-1/7
原式=[1-1/(1-x)]×[(1/x²)-1]÷[-(x+1)/x]
=[1+1/(x-1)]×[(1/x²)-(x²/x²)]×[-x/(x+1)]
=[(x-1+1)/(x-1)]×[(1-x²)/x²]×[-x/(x+1)]
=[x/(x-1)]×[-(x+1)(x-1)/x²]×[-x/(x+1)]
=1
解2题
原式=[(3-m)/(2m-4)]÷[(m+2)-5/(m-2)]
={(3-m)/[2(m-2)]}÷[(m+2)(m-2)/(m-2)-5/(m-2)]
={-(m-3)/[2(m-2)]}÷[(m²-4-5)/(m-2)]
={-(m-3)/[2(m-2)]}×{(m-2)/[(m+3)(m-3)]}
=-1/[2(m+3)]
=-1/[2×(1/2+3)]
=-1/(1+6)
=-1/7
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询