Question

急啊! ! ! ! ! ! !一道初一数学题,求过程和答案。拜托各位帮帮忙啦~~~ ...

急啊! ! ! ! ! ! !一道初一数学题,求过程和答案。拜托各位帮帮忙啦~~~
(x^2-2x-2)(x^2-2x-9)+6
=??????

Answer 1

解：设x²-2x=y。则可化为（y-2）（y-9）+6=y²-11y+24=（y-3）（y-8）=（x²-2x-3）（x²-2x-8）=(x-3)(x+1)(x-4)(x+2)

Answer 2

(x^2-2x-2)(x^2-2x-9)+6
=（x²-2x)²-9(x²-2x)-2(x²-2x)+18+6
=(x²-2x)²-11(x²-2x)+24
=(x²-2x-3)(x²-2x-8)
=(x-3)(x+1)(x-4)(x+2)

Answer 3

(x^2-2x-2)(x^2-2x-9)+6
=(x²-2x)²-11(x²-2x)+18+6
=(x²-2x)²-11(x²-2x)+24
=(x²-2x-3)(x²-2x-8)
=(x-3)(x+1)(x+2)(x-4)

Answer 4

(x^2-2x-2)(x^2-2x-9)+6
=(x^2-2x-2)^2-7(x^2-2x-2)+6
=(x^2-2x-2-6)(x^2-2x-2-1)
=(x^2-2x-8)(x^2-2x-3)
=(x-4)(x+2)(x-3)(x+1)

Answer 5

(x^2-2x-2)(x^2-2x-9)+6
=4x²-2x²-18+6
=0-18+6
=-12