Question

请教一道c语言题，利用递归函数计算x的n次幂。

帮帮我！！！

Answer 1

#include<stdio.h>

int Xn(int x,int n)//x的n次幂(n>=0)
{
if(n=0)return 1;
else if(n=1) return x;
else return(Xn(x,n-1));
}
void main()
{
int a,b,xn;
scanf("%d %d",&a,&b);
xn=Xn(a,b);//a的b次幂
printf("The result is:%d",xn);
}

Answer 2

long mi(int x,int n)
{
if (n=1) return n;
else
return((long)x*mi(x,n-1);
}

Answer 3

#include<stdio.h>
void main()
{
int x,n,sum=1;
scanf("%d%d",&x,&n);
if(n){
for(i=1;i<=n;i++)sum*=x;
}
printf(""%d",sum);
}

Answer 4

#include<stdio.h>
long mi(int x,int n)
{
if (n=1) return n;
else
return((long)x*mi(x,n-1);
}
void main()
{
int x,n,sum=1;
scanf("%d%d",&x,&n);
printf(""%d",mi(x,n));
}