分式的乘除法2、b/a²-9*a+3/b²-b 3、 x²+xy/x-y÷xy/x-y 4、a/a-b*(b-a/b)²
2个回答
展开全部
2
b/(a²-9)*(a+3)/(b²-b)
=b/[(a+3)(a-3)]*(a+3)/[b(b-1)]
=1/[(a-3)*1/(b-1)
=1/[(a-3)(b-1)]
3
(x²+xy)/(x-y)÷(xy)/(x-y)
=x(x+y)/(x-y)×(x-y)/(xy)
=x(x+y)/(xy)
=(x+y)/y
4
a/(a-b)*[(b-a)/b]²
=a/(a-b)*(b-a)²/b²
=a/(a-b)*(a-b)²/b²
=a*(a-b)/b²
5
小明不正确
乘除法是同级运算应该
按前后顺序算
应该为:a÷b×1/b=a/(b×b)=a/b²
b/(a²-9)*(a+3)/(b²-b)
=b/[(a+3)(a-3)]*(a+3)/[b(b-1)]
=1/[(a-3)*1/(b-1)
=1/[(a-3)(b-1)]
3
(x²+xy)/(x-y)÷(xy)/(x-y)
=x(x+y)/(x-y)×(x-y)/(xy)
=x(x+y)/(xy)
=(x+y)/y
4
a/(a-b)*[(b-a)/b]²
=a/(a-b)*(b-a)²/b²
=a/(a-b)*(a-b)²/b²
=a*(a-b)/b²
5
小明不正确
乘除法是同级运算应该
按前后顺序算
应该为:a÷b×1/b=a/(b×b)=a/b²
本回答被提问者采纳
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询