Question

spring web.xml加载多个Spring配置文件怎么写？下面是已经编译通过的单个spring

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.4"
xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<servlet>
<servlet-name>dispatcherServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<!-- 初始化参数 -->
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/dispatcherServlet-servlet.xml</param-value>
</init-param>
<!-- 设定优先级，正数值越小，优先级级别越高 -->
<load-on-startup>1</load-on-startup>
</servlet>

<!-- 拦截所有以do结尾的请求 -->
<servlet-mapping>
<servlet-name>dispatcherServlet</servlet-name>
<url-pattern>*.do</url-pattern>
</servlet-mapping>
</web-app>
怎么加载两个类似dispatcherServlet-servlet.xml的配置文件

Answer 1

<param-value>/WEB-INF/dispatcherServlet-servlet.xml</param-value>里面可以用“ , ”号隔开，Spring加载的时候 paramvalue默认就是数组类型的，而不是字符串，你去试试吧

Answer 2

<param-value>/WEB-INF/applicationContext-*.xml;/WEB-INF/classes/springConfig/applicationContext-*.xml</param-value>
中间用分号隔开

Answer 3

<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/dispatcherServlet-servlet.xml,path+XXXXXXXX.xml</param-value>
</init-param>