Question

若一元二次方程x2+px+q=0有两个实数根x1,x2,则x1+x2=__,x1x2=__.

Answer 1

韦达定理
x1+x2=_-p_
x1x2=_q_

Answer 2

x1+x2=-a/b=-p x1x2=a/c=p 望采纳~

Answer 3

x1+x2=-P,x1x2=Q