Question

设集合P={x|x-x^2>0},Q={x|x^2-2x+1≤0},则P∪Q=?P交Q=?

Answer 1

P: x(x-1)<0, 得：0<x<1
Q: (x-1)^2<=0, 得：x=1
因此
PUQ={x| 0<x<=1}
P∩Q＝Φ

Answer 2

p：x(x-1),得：x在（0,1)
Q:(x-1)^2<=1，得：x<=1
因此
PUQ={xl x<=1}
P∩Q={xl 0<x<=1}