Question

求编个数字转码的JAVA程序，只有9个规则！

密码表:
0 48
1 c8
2 49
3 c9
4 58
5 d8
6 59
7 d9
8 68
9 e8

要求就是对数字按上述规则进行加密！
例如输入306499 就可以转换为c9485958e8e8

邮箱scured@qq.com！感谢~

Answer 1

package testpractice;

import java.util.Scanner;

public class Test
{

/**
* @param args
*/
public static void main(String[] args)
{
Scanner s = new Scanner(System.in);
int number = 0;
while(number >= 0)
{
System.out.println("请输入0~9到的整数：");
number = s.nextInt();
switch(number)
{
case 0:System.out.println("48");
break;
case 1:System.out.println("c8");
break;
case 2:System.out.println("49");
break;
case 3:System.out.println("c9");
break;
case 4:System.out.println("58");
break;
case 5:System.out.println("d8");
break;
case 6:System.out.println("59");
break;
case 7:System.out.println("d9");
break;
case 8:System.out.println("68");
break;
case 9:System.out.println("e8");
break;
default:System.out.println("你输入的错误！");
}

}

}

}

Answer 2

import java.nio.ByteBuffer;
import java.util.HashMap;

public class Test {
private static final HashMap<String,String> nums = new HashMap<String,String>();
static{
nums.put("0", "48");
nums.put("1", "c8");
nums.put("2", "49");
nums.put("3", "c9");
nums.put("4", "58");
nums.put("5", "d8");
nums.put("6", "59");
nums.put("7", "d9");
nums.put("8", "68");
nums.put("9", "e8");
}
public String encipher(String num){
char[] chr = num.toCharArray();
StringBuffer strs = new StringBuffer();
for(int i=0;i<chr.length;i++){
strs.append(nums.get(String.valueOf(chr[i])));
}
return strs.toString();
}
public static void main(String[] args) throws Exception {
Test a = new Test();
System.out.println(a.encipher("2342342"));
}

}

Answer 3

编写一个Java程序，它能产生从0~9的十个数字中随机取出4个不重复的数字import java.util.Random; public class test{ public static void main(,fhnwWH

Answer 4

已发送！尾号554