Question

输入年和天数，输出对应的年、月、日。 例如：输入2000和61，输出2000-3-1。 C语言，谢谢。错在哪里了？

#include<stdio.h>
int main (void)
{
int year,yearday,day,month;
void month_day(int year,yearday,*pmonth,*pday);
printf("请输入年份和天数\n");
scanf("%d%d",&year,&day);
month_day (year,yearday,&month,&day );
printf("%d-%d-%d",year,month,day);
return 0;

}

void month_day(int year,yearday,*pmonth,*pday)
{ int pd,i;
int tab[2][13]=
{
{0,31,28,31,30,31,30,31,31,30,31,30,31}
{0,31,29,31,30,31,30,31,31,30,31,30,31}
}
pd=(year%400==0||year%4==0&&year%100!=0 ); //判定闰年,是闰年pd为1，否为0

for(i=1,yearday>tab[pd][i],i++)
yearday=yearday-tab[pd][i];

*pmonth=i;
*pday=yearday;
}

Answer 1

已通过测试，望采纳。
#include<stdio.h>
int main (void)
{
int year,yearday,day,month;
void month_day(int year,int yearday,int *pmonth,int *pday);
printf("请输入年份和天数\n");
scanf("%d%d",&year,&yearday);
month_day (year,yearday,&month,&day );
printf("%d-%d-%d",year,month,day);
return 0;

}

void month_day(int year,int yearday,int *pmonth,int *pday)
{ int pd,i;
int tab[2][13]=
{
{0,31,28,31,30,31,30,31,31,30,31,30,31},
{0,31,29,31,30,31,30,31,31,30,31,30,31}
};
pd=(year%400==0||(year%4==0&&year%100!=0)); //判定闰年,是闰年pd为1，否为0

for(i=0;yearday>tab[pd][i];i++)
yearday=yearday-tab[pd][i];

*pmonth=i;
*pday=yearday;
}

追问

你好，是因为void month_day(int year,int yearday,int *pmonth,int *pday);
不能 这样写吗void month_day(int year,yearday,*pmonth,*pday);
不是能省略吗，还是有其他问题？希望指出，授人以鱼不如授人以渔，谢谢。

追答

不可以省略，每一个形参都必须有确定的类型
就是能“省略”，那个叫不确定形参个数，形式为void month_day(int year,int yearday...); 函数内仍需注明，只要出现在形参表中都加类型

Answer 2

。。