Question

求教一个函数的极限怎么求

函数[sin(x-1)]的平方数以（x的平方-1）在X趋于1的时候的极限。。函数不好打。用了数学加文字说明。。

Answer 1

lim (sin(x-1))²/(x²-1)
=lim (x-1)²( (sin(x-1))²/(x-1)²) /(x²-1)
=lim (x-1)²((sin(x-1)/(x-1))² /(x²-1)
=lim (x-1)² *1 /(x²-1)
=lim (x-1)/(x+1)
=0