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【(1/2)+(√3/2)i】³
=【cos(π/3)+ i sin(π/3)】³
= cos(3π/3)+ i sin(3π/3)(应用棣莫弗定理)
= cos(π)+ i sin(π)
= -1
=【cos(π/3)+ i sin(π/3)】³
= cos(3π/3)+ i sin(3π/3)(应用棣莫弗定理)
= cos(π)+ i sin(π)
= -1
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解:
(1/2+√3i/2)³
=[(1+√3i)/2]³
=(1+√3i)³/8
=(1+√3i)²(1+√3i)/8
=(1-3+2√3i)(1+√3i)/8
=-2(1-√3i)(1+√3i)/8
=-2(1²-(√3i)²)/8
=-8/8
=-1
(1/2+√3i/2)³
=[(1+√3i)/2]³
=(1+√3i)³/8
=(1+√3i)²(1+√3i)/8
=(1-3+2√3i)(1+√3i)/8
=-2(1-√3i)(1+√3i)/8
=-2(1²-(√3i)²)/8
=-8/8
=-1
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