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两个定值电阻R1和R2,已知R1=nR2,现将这两个电阻串联后接在电压为U的电源两端时,它们两端的电压分别为
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两个电阻串联 则电路总电阻
R=R1+R2=nR2+R2=(1+n)R2
则有
U1=(R1/R)U=(nR2/(1+n)R2))U=(n/(1+n))U
U2=(R2/R)U=(R2/(1+n)R2))U=(1/(1+n))U
R=R1+R2=nR2+R2=(1+n)R2
则有
U1=(R1/R)U=(nR2/(1+n)R2))U=(n/(1+n))U
U2=(R2/R)U=(R2/(1+n)R2))U=(1/(1+n))U
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