Question

C语言：编写1+2+3+...m的函数，利用该函数，求 1+(1+2)+...+(1+2+3+...+n)？

Answer 1

#include <stdio.h>
#include <stdlib.h>

int get_sum(int m)
{
int i = 0;
int sum = 0;
if(m <= 0)
{
return 0;
}
for(i = 1 ; i <= m; i++)
{
sum += i;
}
return sum;
}

int main()
{
int n = 0;
int j =0;
int total =0;
printf("Please input n:\n");
scanf("%d", &n);
if(n < 0)
{
printf("n should be larger than 0\n");
return 1;
};
for(j = 1; j <= n; j++)
{
total += get_sum(j);
}
printf("Total value is : %d\n", total);
return 0;
}

Answer 2

#include <stdio.h>

int count(int m)
{
int i,s=0;
for(i=1;i<=m;i++)
s+=i;
return s;
}

int main()
{
int i,n,s=0;
printf("give n :\n");
scanf("%d",&n);
for(i=1;i<=n;i++)
s += count(i);

printf("s = %d\n",s);

}

Answer 3

main（）
｛int i=1，s=0, n;
printf("请输入n的值");
scanf("%d\n",&n);
while(i<=n)
{i ;s=s i;}
printf("s=%d,\n",s);
}