数学题目,帮忙解答一下!
第一题:1\2+1\6+1\12+1\20+1\30+1\42第二题:1\6+1\12+1\20+1\30+…1\9900...
第一题:1\2 + 1\6 + 1\12 + 1\20 + 1\30 + 1\42
第二题:1\6 + 1\12 + 1\20 + 1\30 +…1\9900 展开
第二题:1\6 + 1\12 + 1\20 + 1\30 +…1\9900 展开
6个回答
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1 =(1-1/2)+(1/2-1/3)+(1/3-1/4)+...+(1/6-1/7)
=1-1/7=6/7
2 =1/2-1/3+1/3-1/4+...+1/99-1/100
=1/2-1/100=49/100
=1-1/7=6/7
2 =1/2-1/3+1/3-1/4+...+1/99-1/100
=1/2-1/100=49/100
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1.
1/2 + 1/6 + 1/12 + 1/20 + 1/30 + 1/42
=1/(1*2) +1/(2*3)+1/(3*4)+1/(4*5)+1/(5*6)+1/(6*7)
=[(1/1)-(1/2)+(1/2)-(1/3)+(1/3)-(1/4)+(1/4)-(1/5)+(1/5)-(1/6)+(1/6)-(1/7)]
=1-(1/7)
6/7;
2.
1/6 + 1/12 + 1/20 + 1/30 +…1/9900
=1/(2*3)+1/(3*4)+1/(4*5)+1/(5*6)+...+1/(99*100)
=[(1/2)-(1/3)+(1/3)-(1/4)+(1/4)-(1/5)+...+(1/99)-(1/100)]
=(1/2)-(1/100)
=49/100.
1/2 + 1/6 + 1/12 + 1/20 + 1/30 + 1/42
=1/(1*2) +1/(2*3)+1/(3*4)+1/(4*5)+1/(5*6)+1/(6*7)
=[(1/1)-(1/2)+(1/2)-(1/3)+(1/3)-(1/4)+(1/4)-(1/5)+(1/5)-(1/6)+(1/6)-(1/7)]
=1-(1/7)
6/7;
2.
1/6 + 1/12 + 1/20 + 1/30 +…1/9900
=1/(2*3)+1/(3*4)+1/(4*5)+1/(5*6)+...+1/(99*100)
=[(1/2)-(1/3)+(1/3)-(1/4)+(1/4)-(1/5)+...+(1/99)-(1/100)]
=(1/2)-(1/100)
=49/100.
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1. =21/42+7/42+3.5/42+2.1/42+1.4/42
=35/42
=5/6
2. =1/2*3+1/3*4+1/4*5+...+1/99*100
=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+...+1/99-1/100
=1-1/100
=99/100
=35/42
=5/6
2. =1/2*3+1/3*4+1/4*5+...+1/99*100
=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+...+1/99-1/100
=1-1/100
=99/100
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1. 6/7
2.49/100
2.49/100
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