Question

一道高一数学对数函数计算题

lg4+lg5lg20+（lg5）的平方

Answer 1

解：(lg4)+lg5*[(lg20)+(lg5)]
=(2lg2)+)(lg5)(lg100)
=(2lg2)+(2lg5)
=2[(lg2)+(lg5)]
=2

Answer 2

原式
=(lg4)+[(lg20)+(lg5)](lg5)
=(2lg2)+(lg100)(lg5)
=(2lg2)+(2lg5)
=2[(lg2)+(lg5)]
=2