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此题如何解答,着急,谢谢大家帮助一下!
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∫x√(1+x²)dx
=(1/2)∫(1+x²)^(1/2)dx²
=(1/2)*(2/3)(1+x²)^(3/2)+C [0,1]
=(1/3)(1+x²)^(3/2) [0,1]
=2√2/3-1/3
=(2√2-1)/3
=(1/2)∫(1+x²)^(1/2)dx²
=(1/2)*(2/3)(1+x²)^(3/2)+C [0,1]
=(1/3)(1+x²)^(3/2) [0,1]
=2√2/3-1/3
=(2√2-1)/3
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