Question

$sql1="insert into yqpp(pp_xx) values('$_POST[content]')"; mysql_query($sql1);

$sql="select * from yqpp where pp_name='$title' and pp_xx='$_POST[content]'";
$result=mysql_query($sql);
$Numbers=mysql_num_rows($result);
if($Numbers==0)//数据库无该记录
{
$sql1="insert into yqpp(pp_xx) values('$_POST[content]')";
mysql_query($sql1);
$sql1="select * from yqpp whereand pp_xx='$_POST[content]'";
$result=mysql_query($sql1);
while($row=mysql_fetch_array($result))
{
echo ("<script>alert(' $pp_name 品牌增加成功！请上传图片');window.location.href='pptp.php?pp_id=$row[0]&pp_name=$pp_name&pp_xx=$pp_xx';</script>");
}

}else
{
echo ("<script>alert(' $pp_name 品牌已经存在了，不用重复添加');window.location.href='addpp.php';</script>");
}

Answer 1

没有问题......

Answer 2

最好是把出现的问题表述清楚

Answer 3

你想问什么？

Answer 4

xx