Question

已知函数f(x)=(x-k)^2·e^x/k跪求求导步骤

Answer 1

f(x)=(x-k)^2·e^x/k
f'(x) =(1/k) (e^x)[ ( 2(x-k) + (x-k)^2) ]

追问

答案是1/k(x^2-k^2)e^x/k,我是不知道具体步骤，复合的我忘了怎么解了

追答

let
u=(x-k)^2
u' = 2(x-k)
v= e^x
v' =e^x
f(x) = (1/k)uv
f'(x) = (1/k)( uv'+vu')
= (1/k)( (x-k)^2 .e^x + 2(x-k) e^x)
=(1/k)e^x( (x-k)^2 + 2(x-k) )