Question

c语言编程x - x2/2! + x3/3! + ... + (-1)n-1xn/n!

Answer 1

double x;
int n;
printf("请输入n和x的值:\n");
scanf("%d%lf",&n,&x);
double sum = 0;
double item = x;
long long tmp = 1;//VC的话这里用 __int64 tmp = 1;
int flag = 1;
for(int i = 1;i < =n;i++)
{
tmp *= i;
sum += flag * item / tmp;
item *= x;
flag *= -1;
}
printf("%lf\n",sum);

Answer 2

对不起 我只会pascal的

Answer 3

#include<stdio.h>
#include<math.h>
void main()
{
int n,i,j=1,k=-1;
double x,sum=0;
scanf(%d%f",&n,&x)
for(i=1;i<=n;i++)
{
j*=i;
k=k*(-1);
sum+=(x*k*i)/j;
printf("sum=%f/n",sum);
}
}