Question

初中分式的运算 要过程 追加40分 谢谢啦

(x/2y)^2*y/2x-x/y^2/2y^2/x

(x/x+y+2y/x+y)*xy/x+2y/(1/x+1/y)

(1/a+1/b)^2/(1/a^2-1/b^2)

Answer 1

(x/2y)^2*y/2x-x/y^2/(2y^2/x)

=x^2/4y^2*y/2x-x/y^2*(x/2y^2)

=x/8y-x^2/2y^4

(x/x+y+2y/x+y)*xy/x+2y/(1/x+1/y)

=(x+2y)/(x+y)*xy/(x+2y)/[(x+y)/xy]

=xy/(x+y)*xy/(x+y)

=x^2y^2/(x+y)^2

(1/a+1/b)^2/(1/a^2-1/b^2)

=(1/a+1/b)^2/[(1/a+1/b)(1/a-1/b)]

=(1/a+1/b)/(1/a-1/b)

=(a+b)/ab/[(b-a)/ab]

=(a+b)/(b-a)

第一和第二题有点看不清楚分子与分母。