Question

1：化简：a－b分之a＋b－a分之b＋12：化简：4y－8分之y－3除以（y＋2－y－2分之5）

Answer 1

a－b分之a＋b－a分之b＋12
=a/(a-b)-b/(a-b)+12
=(a-b)/(a-b)+12
=1+12
=13

4y－8分之y－3除以（y＋2－y－2分之5）
=[(y-3)/(4y-8)]÷[（y^2-9)/(y-2)]
=[(y-3)/4*(y-2)]÷[(y-3)(y+3)/(y-2)]
=[(y-3)/4*(y-2)]×[(y-2)/(y-3)(y+3)]
=1/[4(y+3)]
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Answer 2

a－b分之a＋b－a分之b＋12a-b
=a/(a-b)+b/(b-a)+12
=a/(a-b)-b/(a-b)+12
=(a-b)/(a-b)+12
=1+12
=13
4y－8分之y－3除以（y＋2－y－2分之5）
=(y-3)/(4y-8)÷[y+2-5/(y-2)]
=(y-3)/4(y-2)÷[(y^2-9)/(y-2)
=(y-3)/4(y-2)÷[(y+3)(y-3)/(y-2)]
=1/[4(y+3)]

Answer 3

1、（a-b-12）/（a-b)