Question

编写一个程序完成两个数的四则运算

Answer 1

#include<stdio.h>int main(){
    int a,b;
    printf("请输入两个数\n:");
    scanf("%d %d",&a,&b);
    
    //加法    
    printf("%d+%d=%d\n",a,b,a+b);
    
    //减法    
    printf("%d-%d=%d\n",a,b,a-b);
    
    //乘法    
    printf("%d*%d=%d\n",a,b,a*b);
    
    //除法    
    if(0 == b)
        printf("除数不能为0\n");
    else
        printf("%d/%d=%.2f\n",a,b,(float)a/b);
    return 0;}

Answer 2

#include<stdio.h>
void main()
{
float a=0,b=0,c=0;
char d;
printf("输入简单的四则运算表达式:\n");
scanf("%f%c%f",&a,&d,&b);
switch(d)
{
case'+': c=a+b;break;
case'-': c=a-b;break;
case'x':
case'*': c=a*b;break;
case'/': if(b>0) c=a/b;break;
default:break;
}
printf("%g%c%g=%g\n",a,d,b,c);
}