Question

mathematica如何定有一个分段函数？

Wp = 3*2*Pi;
Ws = 12*2*Pi;
Rp = 0.1;
Rs = 60;
\!\(TraditionalForm\`Cn = Piecewise[{{cos(Njie\ \(
\*SuperscriptBox[\(cos\), \(-1\)](x)\)), \*
TemplateBox[{"x"},
"Abs"] < 1}, {Cosh[Njie*ArcCosh[x]] {\*
TemplateBox[{"x"},
"Abs"] > 1}}}]\);
自己搞明白了，格式打错了
Cn=Piecewise[{{cos(Njie cos^-1(x)),\[LeftBracketingBar]x\[RightBracketingBar]<1},{Cosh[Njie*ArcCosh[x]],\[LeftBracketingBar]x\[RightBracketingBar]>1}}]
就对了，括号的问题

Answer 1

Cn=Piecewise[{{Cos[Njie ArcCos[x]],Abs[x]<1},{Cosh[Njie*ArcCosh[x]],x>1}}]

追问

我原来就是这样做的，出血如下错误

追答

Cos大写，后面用[],你可以直接复制我的,cos反函数是ArcCos