
七下几道数学题!!拜托,很急!
(4mn的三次方+6m的三次方n)÷(2n²+3m²)=【(2a-1)²-(3a-1)²】÷(5a-2)=解下列方程①49x...
(4mn的三次方+6m的三次方n)÷(2n²+3m²)=
【(2a-1)²-(3a-1)²】÷(5a-2)=
解下列方程
①49x²-25=0 ②4x²=8x 展开
【(2a-1)²-(3a-1)²】÷(5a-2)=
解下列方程
①49x²-25=0 ②4x²=8x 展开
1个回答
展开全部
(4mn^3+6m^3n)/(2n^2+3m^2)
=2mn(2n^2+3m^2)/(2n^2+3m^2)
=2mn
[(2a-1)^2-(3a-1)^2]/(5a-2)
={2a-1+3a-1)(2a-1-3a+1)/(5a-2)
=-a(5a-2)/(5a-2)
=-a
解方程:
(1)49x^2-25=0
(7x+5)(7x-5)=0
x1=-5/7 x2=5/7
所以原方程的解是:
x1=-5/7 x2=5/7
(2) 4x^2=8x
x^2-2x=0
x(x-2)=0
x1=0 x2=2
所以原方程的解是:
x1=0 x2=2
=2mn(2n^2+3m^2)/(2n^2+3m^2)
=2mn
[(2a-1)^2-(3a-1)^2]/(5a-2)
={2a-1+3a-1)(2a-1-3a+1)/(5a-2)
=-a(5a-2)/(5a-2)
=-a
解方程:
(1)49x^2-25=0
(7x+5)(7x-5)=0
x1=-5/7 x2=5/7
所以原方程的解是:
x1=-5/7 x2=5/7
(2) 4x^2=8x
x^2-2x=0
x(x-2)=0
x1=0 x2=2
所以原方程的解是:
x1=0 x2=2
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