已知x=√2+1分之√2-1,y=√2-1分之√2+1，则x平方-xy+y平方
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x=(√2-1)/(√2+1)
=(√2-1)(√2-1)/(√2+1)(√2-1)
=(3-2√2)/(1)
=3-2√2
y=(√2+1)/(√2-1)
=(√2+1)(√2+1)/(√好孝橡2+1)(√2-1)
=(3+2√2)/(1)
=3+2√2
x²-xy+y²友旁
=(x+y)²-3xy
=6²-3×1
=36-3
=33
满意请慎辩轻戳此处
↓
=(√2-1)(√2-1)/(√2+1)(√2-1)
=(3-2√2)/(1)
=3-2√2
y=(√2+1)/(√2-1)
=(√2+1)(√2+1)/(√好孝橡2+1)(√2-1)
=(3+2√2)/(1)
=3+2√2
x²-xy+y²友旁
=(x+y)²-3xy
=6²-3×1
=36-3
=33
满意请慎辩轻戳此处
↓
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