Question

怎么用C++定义一个datetime类，使其对象可以显示当前系统时间和日期 ？谢谢

Answer 1

#include<time.h>
#include<stdio.h>
class datetime
{
public:
int year;
int month;
int day;
int hour;
int min;
int sec;
datetime()
{
struct tm* ptm;
time_t ltime;
time(<ime);
ptm = localtime(<ime);
year = ptm->tm_year+1900;
month = ptm->tm_mon+1;
day = ptm->tm_mday;
hour = ptm->tm_hour;
min = ptm->tm_min;
sec = ptm->tm_sec;
}
void output()
{
printf("%.4d/%.2d/%.2d %.2d:%.2d:%.2d\n",year,month,day,hour,min,sec);
}
};
void main(void)
{
datetime d;
d.output();
}

追问

你自己编译过了吗？？

追答

真是个有趣的现象我写的 time(& l t ime); 和localtime(& l time);会被百度转换，大概& l t就是
#include
class datetime
{
public:
int year;
int month;
int day;
int hour;
int min;
int sec;
datetime()
{
struct tm* ptm;
time_t m;
time(&m);
ptm = localtime(&m);
year = ptm->tm_year+1900;
month = ptm->tm_mon+1;
day = ptm->tm_mday;
hour = ptm->tm_hour;
min = ptm->tm_min;
sec = ptm->tm_sec;
}
void output()
{
printf("%.4d/%.2d/%.2d %.2d:%.2d:%.2d\n",year,month,day,hour,min,sec);
}
};
void main(void)
{
datetime d;
d.output();
}

Answer 2

路过，我也有这个需求。谢谢。