Question

C# winform XML加载Treeview

XML格式：
<xml>
<c:xml id="1" name="ceshi1" group = "1" uecode = "00001">
<c:xml id="2" name="ceshi1.1" group = "2" uecode = "0000100001">
<c:xml id="3" name="ceshi1.2" group = "2" uecode = "0000100002">
<c:xml id="4" name="ceshi1.1.1" group = "3" uecode = "00001000100001">

要详细代码，谢谢！如果答案满意可以再加分！

</xml>

Answer 1

using System.XML;

public XmlDocument XmlDoc;
XmlDoc = new XmlDocument();
XmlDoc.Load(xmlfile) ; //xmlfile 为xml文件的绝对路径
XmlNode node = XmlDoc.SelectSingleNode("根节点的名称");
XmlNodeList nodelist = node.ChildNodes;
//写一个方法递归遍历子节点 就可以 了
public void Analysis(XmlNodeList xlist)
{
foreach(XmlNode node in xlist)
{
.................
Analysis("");
}
}

Answer 2

这是作业吧！
去用工读书去！