Question

php中问号传参为什么接收不到值?

传页面:
<a href="admin_username_recompose.php?admin_id=<?php echo $array['admin_id']?>">修改</a>

接收页面:
<?php
require("../inc/conn.php");
$id=(int)$_GET['admin_id'];
//echo"$id";
//exit;
$rs=mysql_query('SELECT *
FROM admin
WHERE admin_id=$.id',$conn);
$array=mysql_fetch_array($rs);
?>

Answer 1

传页面:
<a href="admin_username_recompose.php?admin_id=<?php echo $array['admin_id'];?>">修改</a>

接收页面:
<?php
require_once("../inc/conn.php");
$id=intval($_GET['admin_id']);

$rs=mysql_query("SELECT *
FROM `admin`
WHERE `admin_id`='".$id."'",$conn);
$array=mysql_fetch_array($rs);
?>

Answer 2

传页面:
<a
href="admin_username_recompose.php?admin_id=<?php
echo
$array['admin_id'];?>">修改</a>
接收页面:
<?php
require_once("../inc/conn.php");
$id=intval($_GET['admin_id']);
$rs=mysql_query("SELECT
*
FROM
`admin`
WHERE
`admin_id`='".$id."'",$conn);
$array=mysql_fetch_array($rs);
?>

Answer 3

<a href="admin_username_recompose.php?admin_id=<?php echo $array['admin_id']?>">修改</a>

改为:

<a href="admin_username_recompose.php?admin_id=<?php echo $array['admin_id'];?>">修改</a>

少了结束符

Answer 4

<?php
require("../inc/conn.php");
$id=intval($_GET['admin_id']);

$rs=mysql_query('SELECT * FROM admin WHERE admin_id=$id',$conn);
$array=mysql_fetch_array($rs);
?>

Answer 5

因为只有一行代码，有没有结束符应该没影响．
是不是 $array['admin_id'] 本身就是空的呢？