Question

函数connectAB将b数组所有元素按原顺序分别存放到a数组a[n-1]元素的后面，使得a数组变成n+m个元素

#include "stdio.h"
const int N0=100;

void connectAB( int a[], int *n, int b[], int *m)
{
//************************************************

//=================================================
}

int main()
{ int n, a[2*N0], m, b[N0], i;
freopen("C6_1B.in", "r", stdin);
freopen("C6_1B.out", "w", stdout);
scanf("%d", &n);
for( i=0; i<n; i++)
scanf("%d", &a[i]);

scanf("%d", &m);
for( i=0; i<m; i++)
scanf("%d", &b[i]);

connectAB( a, &n, b, &m);

for( i=0; i<n-1; i++)
printf("%d ", a[i]);
printf("%d\n", a[n-1]);

return 0;
}

Answer 1

晕晕晕