Question

已知|x-8y|+2(4y-1)²+3|8z-3x|=0，求x+y+z的值?简便方法用加减直接求出x+y+z

Answer 1

|x-8y|+2(4y-1)²+3|8z-3x|=0
由非负性
x-8y=0......(1)
4y-1=0......(2)
8z-3x=0......(3)
由(2)得
y=0.25
代入(1)得
x-2=0
x=2
代入(3)得
8z-6=0
z=0.75

解得
x=2
y=0.25
z=0.75
则
x+y+z=3

Answer 2

x-8y=0 4y-1=0 8z-3x=0
y=1/4
x=2
z=3/4
x+y+z=2+1/4+3/4=3

Answer 3

x+y+z=2+ + =3 因为|x-8y|≥0，2(4y-1)^2≥0，3|8z-3x可求得：x=2，y=1/4，z=3/4 x+y+z=3 因为丨x-8y丨大于或